A Leg Of An Isosceles Triangle Is 14 Cm Longer Than The Base.If The Perimeter Is 68 Cm What Is The Length Of The Base

A leg of an isosceles triangle is 14 cm longer than the base.If the perimeter is 68 cm what is the length of the base

 

Answer:

The length of the base is 13 1/3 centimeters or 13.333 centimeters.

Computation:

Given that it is an isosceles triangle, two sides should be equal.

Representation

\left\begin{array}{ccc}Side1\:(Base)&\to&x\\Side2&\to&x+14\\Side3&\to&x+14\end{array}\right

Solution

x+(x+14)+(x+14)=68\\3x+28=68\\3x=68-28\\3x=40\\x=40/3=\boxed{13\frac{1}{3}\:cm}


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